$(a)\;6\times10^{19}\qquad(b)\;6\times10^{18}\qquad(c)\;6\times10^{17}\qquad(d)\;6\times10^{13}$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

At constant V and T

$\large\frac{P_1}{n_1} = \large\frac{P_2}{n_2}$

$\large\frac{100}{\large\frac{12}{120}} = \large\frac{0.01}{n_2}$

$(n_1 = \large\frac{12}{120})$

$n_2 = \large\frac{0.01}{1000}$

$\;\;\;\;=1\times10^{-5}$

No. of molecules left = $6.02\times10^{23}\times10^{-5}$

$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=6.02\times10^{18}$

Hence answer is (b)

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...