logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The number of lone pairs in $XeF_2$

$\begin{array}{1 1}(a)\;1&(b)\;2\\(c)\;3&(d)\;0\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
According to VSPER theory
Total $e^-$ in $Xe$:$8e^-$
In $XeF_2$ b.p=2$(2e^-)$
l.p=3$(3\times 2e^-=6e^-)$
The no of lone pairs in $XeF_2$ is 3.
Hence (c) is the correct answer.
answered Mar 5, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...