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Hydrogenation of the below compound in the presence of poisoned palladium catalyst gives,


$\begin {array} {1 1} (A)\;\text{ Optically active compound}\\ (B)\;\text{An optically in active compound} \\ (C)\;\text{ A racemic mixture} \\ (D)\;\text{A diastereomeric mixture} \end {array}$

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Due to cis-addition of the triple bond. the reduced product has a plane of symmetry and hence is optically inactive.
So it is an optically in active compound
Hence b is the correct anwer.
answered Mar 5, 2014 by meena.p

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