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Which of the following is correct order for the stability of the divalent cations

$\begin{array}{1 1}(a)\;Ge^{2+} < Sn^{2+} < Pb^{2+}\\(b)\; Sn^{2+} < Ge^{2+} < Pb^{2+}\\(c)\;Sn^{2+} < Pb^{2+} < Ge^{2+}\\(d)\;Pb^{2+} < Sn^{2+} < Ge^{2+}\end{array}$

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1 Answer

inert pair effect increases as we move down the group.Consequently the stability of the divalent cations is in the order : $Ge^{2+} < Sn^{2+} < Pb^{2+}$
Hence (a) is the correct answer.
answered Mar 5, 2014 by sreemathi.v
 

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