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# An organic compound contains $C=40 \%,O=53.34\%$ and $H-6.60 \%$ . The empirical formula of the compound is :

$(a)\;CH_2O \\(b)\;CHO \\(c)\;CH_4O_2 \\(d)\; C_2H_2O$

Toolbox:
• Step 1. If you have masses go onto step 2. If you have % composition of the elements. Assume the mass to be 100g, so the % becomes grams.
• Step 2. Determine the moles of each element.
• Step 3. Determine the mole ratio by dividing each elements no. of moles by the smallest value from step 2.
• Step 4. Double, triple, … to get an integer if they are not all whole numbers
Empirical formal $=CH_2O$
Hence a is the correct answer.
edited Mar 25, 2014