logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The following is the percentage composition of a compound. $Na = 16.08 \%, C = 4.19 \%, O = 16.78 \%$ and $H_2O = 62.95 \%$ . Its molecular formula is

$ (a)\;Na_2CO_3 \\(b)\;Na_2CO_3.H_2O \\(c)\;Na_2CO_3.10H_2O\\(d)\;Na_2CO_3.5H_2O$
Can you answer this question?
 
 

1 Answer

0 votes
Toolbox:
  • Step 1. If you have masses go onto step 2. If you have % composition of the elements. Assume the mass to be 100g, so the % becomes grams.
  • Step 2.. Determine the moles of each element.
  • Step 3.. Determine the mole ratio by dividing each elements no. of moles by the smallest value from step 2.
  • Step 4. Double, triple, … to get an integer if they are not all whole numbers.
image
$\therefore$ Empirical Formula = $Na_2CO_3.10H_2O$
Hence (C) is the correct answer.
answered Mar 5, 2014 by meena.p
edited Mar 25, 2014 by mosymeow_1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...