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The number of $\sigma$-bonds and $\pi$-bonds in $XeO_4$ are

$\begin{array}{1 1}(a)\;4\sigma\text{ bonds and }o\pi\text {bonds}\\(b)\;4\sigma\text{ bonds and }4\pi\text {bonds}\\(c)\;2\sigma\text{ bonds and }2\pi\text {bonds}\\(d)\;0\sigma\text{ bonds and }4\pi\text {bonds}\end{array}$

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According to VSEPR theory in $XeO_4$ there are $4\sigma$ bonds and $4\pi$ bonds in tetrahedral structure of $XeO_4$
Hence (b) is the correct answer.
answered Mar 5, 2014 by sreemathi.v

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