# The hybridisation of Sn in $SnCl_6^{2-}$ is

$\begin{array}{1 1}(a)\;sp^3d^3&(b)\; sp^3d^2\\(c)\;dsp^2&(d)\;sp^3d\end{array}$

$SnCl_6^{2-}$ is in octahedral shape with $sp^3d^2$ hybridisation.
Hence (b) is the correct answer.