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Questions  >>  CBSE XII  >>  Math  >>  Integrals
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Q)

$\Large \int e^x\bigg(\frac{1-x}{1+x^2}\bigg)^2 \normalsize dx$ is equal to

$\begin{array}{1 1} (A)\;\frac{e^x}{1+x^2}+C & (B)\;\frac{-e^x}{1+x^2}+C\\(C)\;\frac{e^x}{(1+x^2)^2}+C & (D)\;\frac{-e^x}{(1+x^2)^2}+C \end{array} $

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