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# The number of enantiomers of the compound $CH_3CHBrCHBrCOOH$ is

$(a)\;0 \\(b)\;1 \\(c)\;3 \\(d)\;4$
Can you answer this question?

There are two chiral carbons.
Hence the number of isomers are $2^2=4$
Hence d is the correct answer.
answered Mar 5, 2014 by