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Q)

The number of enantiomers of the compound $CH_3CHBrCHBrCOOH$ is

$ (a)\;0 \\(b)\;1 \\(c)\;3 \\(d)\;4 $

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A)
There are two chiral carbons.
Hence the number of isomers are $2^2=4$
Hence d is the correct answer.
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