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The volume occupied by 1 mole of gas at 1 bar pressure and 273.15K is.....

$(a)\;22.7litre\qquad(b)\;22.4 litre\qquad(c)\;20.4litre\qquad(d)\;24.4litre$

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1 bar = 0.0987 atm
PV = RT
$1\times22.4 = R\times 273$
(at P = 1 atm , V = 22.4)
$0.987\times = R\times273$
$V = \large\frac{22.4}{0.987}$
$\;\;\;\;\;\;\;=22.7\;litre$
Hence answer is (a)
answered Mar 5, 2014 by sharmaaparna1
 

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