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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Electromagnetic Waves
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A sinusoidal electromagnetic plane wave travels through the empty space in $x$ - direction. The electric wave is polarized in the $y$ - direction frequency of waves is $1.5\: GHz$. At a certain point $P$ in space, the oscillating $E_y$ attains a maximum magnitude $E_o = 6.3 \: m V/m$ \[\] The direction of magnetic field vector is along?

$\begin {array} {1 1} (a)\;B = 2.1 \times 10^{-5} \cos \bigg[2\pi \large\frac{(x-ct)}{\lambda} \bigg]k & \quad (b)\;B = 1.4 \times 10^{-7} \cos \bigg[4 \pi \large\frac{(x-ct)}{\lambda} \bigg]i \\ (c)\;B = 1.4 \times 10^{-5} \cos \bigg[4 \pi \large\frac{(x-ct)}{\lambda} \bigg]j & \quad (d)\;B = 2.1 \times 10^{-7} \cos \bigg[2 \pi \large\frac{(x-ct)}{\lambda} \bigg]i \end {array}$

 

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1 Answer

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$B = B_o \cos \bigg[\large\frac{2 \pi( x-ct)}{\lambda} \bigg]$ along Z axis
Here,$ B_o =E_o/c = 2.1 \times 10^{-5}T$
Ans : (a)

 

answered Mar 5, 2014 by thanvigandhi_1
edited Oct 8, 2014 by thagee.vedartham
 

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