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Total number of isomers of $C_4H_{10}O$ will be

$ (a)\;4 \\(b)\;5 \\ (c)\;6 \\ (d)\;7 $
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$C_4H_{10}O$ satisfies the general formula $C_n H_{2n+2}O$.
It is either a monohydric alcohol or an ether.
Four structural isomers of alcohol and three structural isomers of ethers are possible. They are:
1. butan-1-ol
2. butan-2-ol
3. 2-methyl-propan-1-ol
4. 2,2dimethyl-propan-2-ol
5. diethyl ether
6. methyl 1-propyl ether
7. methyl 2-propyl ether
Hence 7 is the correct answer.
Hence, (D) is the correct answer.
answered Mar 5, 2014 by meena.p
edited Mar 25, 2014 by mosymeow_1

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