Browse Questions

# An organic compound contains carbon, hydrogen and oxygen . Its elemental analysis gave C, $38.71\%$ and $H, 9.67 \%$ The empirical formula of the compound would be

$(a)\;CHO \\(b)\;CH_4O \\ (c)\;CH_3O \\ (d)\;CH_2O$

Toolbox:
• Step 1. If you have masses go onto step 2. If you have % composition of the elements. Assume the mass to be 100g, so the % becomes grams.
• Step 2. Determine the moles of each element.
• Step 3. Determine the mole ratio by dividing each elements no. of moles by the smallest value from step 2.
• Step 4. Double, triple, … to get an integer if they are not all whole numbers
Hence the empirical formula of the compound would be $CH_3 O$
Hence c is the correct answer.
edited Mar 25, 2014