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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Atoms
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If activity of a radioactive substance's $\;A_{1}\;$ at time $\;t_{1}\;$ & $\;A_{2}\;$ at time $\;t_{2}\;$ $\;(> t_{1})\;$ . Its decay constant is $\;\lambda\;$ . Then no . of atoms decayed between time $\;t_{1}\;$ & $\;t_{2}\;$ are


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Answer : (a) $\;\large\frac{R_{1}-R_{2}}{\lambda}$
Explanation :
$A_{1}=\lambda\; N_{1} \qquad \; N_{1}=\large\frac{A_{1}}{\lambda}$
and $\; A_{2}=\lambda N_{2} \qquad \; N_{2}=\large\frac{A_{2}}{\lambda}$
No . of atoms decayed = $\;N_{1}-N_{2}$
answered Mar 6, 2014 by yamini.v

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