$(a)\;1\qquad(b)\;4\qquad(c)\;3\qquad(d)\;5$

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Answer : (a) 1

Explanation :

Let

$\lambda x=\lambda \qquad$ & $\qquad\; \lambda y=2 \lambda$

Initially rate of disintegration of X is $\;\lambda N_{0}\;$ and that of Y is $\;2 \lambda N_{0}\;.$

After one half life of X , rate of disintegration of X will becomes $\;\large\frac{\lambda N_{0}}{2}\;$ and that of Y would also be $\;\large\frac{\lambda N_{0}}{2}\;$ ( half - life of B=$\large\frac{1}{2}\;$ half life of A )

So after one half of A or two half lives of B

$(-\large\frac{dN}{dt})_{A}=(-\large\frac{dN}{dt})_{B}$

$n=1$

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