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The bonds between carbon atom (1) and carbon atom (2) in compound $N \equiv C-CH =CH_2$ involves the hybrid is :

$ (a)\;SP^2\;and\;SP^2 \\(b)\;SP^3\;and\;SP \\ (c)\;SP\;and\;SP^2 \\ (d)\;SP\;and\;SP $

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A)
$N = C - CH = CH_2$
$C - SP; \quad SP^2=CH; \quad SP^2=CH_2$
Hence c is the correct answer.
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