Browse Questions

# In a radioactive process nucleus X finally transforms into a stable nucleus Y . Then X & Y can be :

$(a)\;isobars\qquad(b)\;isotopes\qquad(c)\;isotones\qquad(d)\;None$

Explanation :
A & B can be isotopes if no . of $\;\beta-\;$ decays is two times no .of $\;\alpha - \;$ decays .