# In a radioactive process nucleus X finally transforms into a stable nucleus Y . Then X & Y can be :

$(a)\;isobars\qquad(b)\;isotopes\qquad(c)\;isotones\qquad(d)\;None$

## 1 Answer

Answer : (b ) isotopes
Explanation :
A & B can be isotopes if no . of $\;\beta-\;$ decays is two times no .of $\;\alpha - \;$ decays .
answered Mar 6, 2014 by

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