# A cylinder was filled with gaseous mixture containing $CO$ and $N_2$ . The ratio of their partial pressure in cylinder are:

$(a)\;1:1\qquad(b)\;1:2\qquad(c)\;2:1\qquad(d)\;1:3$

## 1 Answer

$P'_{N_2} = P_T \times mole\;fraction\;of\;N_2$
$P'_{CO} = P_T \times mole\;fraction\;of\;CO$
$\large\frac{P'_{CO}}{P'_{N_2}} = \large\frac{mole\;fraction\;of\;N_2}{mole\;fraction\;of\;CO}$
$\;\;\;\;\;\;\;\;\;=\large\frac{moles\;of\;N_2}{moles\;of\;CO}$
$\;\;\;\;\;\;\;\;\;\;=\large\frac{\large\frac{w}{28}}{\large\frac{w}{28}}$
$\;\;\;\;\;\;\;\;\;\;=1:1$
Hence answer is (a)
answered Mar 6, 2014

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