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The ratio of rates of diffusion of propane and nitrogen (I) oxide at same P and T is

$(a)\;1:2\qquad(b)\;2:1\qquad(c)\;1:1\qquad(d)\;2:3$

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$M_{CH_3CH_2CH_3} = 44$
$M_{N_2O} = 44$
$\therefore \large\frac{r_1}{r_2} = \sqrt{\large\frac{M_{C_3H_8}}{M_{N_2O}}}$
$\;\;\;\;\;\;=\sqrt{\large\frac{44}{44}}$
$\;\;\;\;\;\;\;=1$
Hence answer is (c)
answered Mar 6, 2014 by sharmaaparna1
 

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