$N_2$ bond order is 3
It has no unpaired electrons.
$N_2$ electronic configuration :$(\sigma 1s)^2 < (\sigma ^*1s)^2 < (\sigma 2s)^2 < (\sigma^* 2s)^2 < (\pi 2p_x^2=\pi 2p_y^2) < (\sigma 2p_z)^2$
**** is $\sigma 2p_z$
Lumo is $2p\pi_x^*,2p\pi_y^*$
Hence (d) is the correct answer.