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The ratio of average speed of an oxygen molecule to the RMS speed of a nitrogen molecule at the same temperature is :

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$U_{av}\;\;\;O_2 = \sqrt{[\large\frac{8RT}{\pi \times 32}]}$
$U_{rms}\;\;\;N_2 = \sqrt{[\large\frac{3RT}{28}]}$
$\large\frac{U_{av}\;\;O_2}{U_{rms}\;\;N_2} = \sqrt{[\large\frac{8\times28}{\pi \times32\times3}]}$
Hence answer is (b)
answered Mar 6, 2014 by sharmaaparna1

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