Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The number of $\sigma$ and $\pi$-bonds between two carbon atoms in $CaC_2$ is

$\begin{array}{1 1}(a)\;\text{one }\pi\text{-bond and one }\sigma\text{ bond}\\(b)\;\text{two }\sigma\text{-bonds and one }\pi\text{ bond}\\(c)\;\text{two }\pi\text{-bonds and one }\sigma\text{ bond}\\(d)\;\text{three }\sigma\text{-bonds and no }\pi\text{ bond}\end{array}$

Can you answer this question?

1 Answer

0 votes
$CaC_2\rightarrow Ca^{2+}+C_2^{2-}$
$[C\equiv C]^{2-}$ (i.e) Two $\pi$-bonds and $\sigma$ -bond.
Hence (c) is the correct answer.
answered Mar 6, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App