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Which of the following arrangement shows the correct order of increasing stability ?

$ (a)\;N^{2+} < AS^{2+} < Sb^{2+} < Bi^{2+} \\(b)\;Zn^{2+} < Cu^{2+} < AS^{2+} < Bi^{2+} \\ (c)\;Cu^{2+} < CO^{2+} < P^{2+} < N^{2+} \\ (d)\;C^{2+} < Ge^{2+} < Sn^{2+} < Pb^{2+} $

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The correct order of increasing stability is : $C^{2+} < Ge^{2+} < Sn^{2+} < Pb^{2+} $
Hence d is the correct answer.
answered Mar 6, 2014 by meena.p
 

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