Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The first , second, third and fourth ionization energies of a given element are $80,2.43,3.66$ and $25.03 \;MJmol$ respectively

$ (a)\; \text {Boron} \\(b)\;\text {Carbon}\\ (c)\;\text {Aluminium}\\ (d)\;\text {Ditrogen} $
Can you answer this question?

1 Answer

0 votes
Boron is correct.
Hence a is the correct answer.
answered Mar 6, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App