# The electronic affinity values (in KJ molt) of 3 halogens X,Y,Z are respectively $-349,-333,-325$. Then X and Y are Z respectively

$(a)\;F_2,Cl_2\;and\;Br_2 \\(b)\;Cl_2,F_2,Br_2 \\ (c)\;Cl_2,Br_2,F_2 \\ (d)\;Br_2,Cl_2,F_2$

Solution :
The electronic affinity values (in KJ molt) of 3 halogens X,Y,Z are respectively −349,−333,−325−349,−333,−325.
Then X and Y are Z respectively
$Cl_2,F_2,Br_2$ is correct answer.
In IB group all elements are metals.
edited Oct 23, 2017 by meena.p