Browse Questions

# The bond angle of $O-Xe-F$ in $XeOF_4$ is

$\begin{array}{1 1}(a)\;90^{\large\circ}&(b)\; 120^{\large\circ}\\(c)\;72^{\large\circ}&(d)\;90^{\large\circ},120^{\large\circ}\end{array}$

$O-Xe-F$ bond angle is $90^{\large\circ}$
Hence (a) is the correct answer.