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The lone pair of electron is located in $XeF_6$ geometry is

$\begin{array}{1 1}(a)\;\text{In equatorial position}\\(b)\;\text{In axial position}\\(c)\;\text{Both axial and equatorial positions are with equal probability}\\(d)\;\text{None of the above}\end{array}$

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Pentagonalbipyramidal shape of $XeF_6$ with one axial lone pair.
Hence (b) is the correct answer.
answered Mar 6, 2014 by sreemathi.v

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