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The hybridisation of I in $IF_7$ molecule is

$\begin{array}{1 1}(a)\;sp^3d^3&(b)\;d^3sp^3\\(c)\;sp^2d^4&(d)\;d^4sp^2\end{array}$

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Pentagonalbipyramidal $IF_7$ molecule with $sp^3d^3$ hybridisation.
Hence (a) is the correct answer.
answered Mar 6, 2014 by sreemathi.v
 

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