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The electronic configuration of the atom having max difference in first and 2nd ionization energies.

$ (a)\;1S^2,2S^2,2P^1 \\(b)\; 1S^2,2S^2,2P^6,3S^1 \\ (c)\;1S^2,2S^2,2P^3 \\ (d)\;1S^2,2S^2,2P^3,2S^2$

1 Answer

$ 1S^2,2S^2,2P^6,3S^1$ is correct
Hence b is the correct answer.
answered Mar 7, 2014 by meena.p
 

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