Browse Questions

Which of the following is the correct order of bond angle

$\begin{array}{1 1}(a)\;H_2S > H_2Te > H_2Se\\(b)\; H_2S > H_2Se > H_2Te\\(c)\;H_2Te > H_2Se > H_2S\\(d)\;H_2Se > H_2Te > H_2S\end{array}$

Can you answer this question?

$H_2S(=92.2^{\large\circ}) > H_2Se(=91.0^{\large\circ} )> H_2Te(=90^{\large\circ})$
Hence (b) is the correct answer.
answered Mar 7, 2014