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The correct order of increasing $C-O$ bond length of $CO,CO_3^{2-},CO_2$ is :

$\begin{array}{1 1}(a)\;CO_2 < CO_3^{2-} < CO\\(b)\; CO_3^{2-} < CO_2 < CO\\(c)\;CO < CO_2 < CO_3^{2-}\\(d)\;CO < CO_3^{2-} < CO_2\end{array}$

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$\text{Bond length}\propto \large\frac{1}{\text{Bond order}}$
$CO$ bond order is 3.
$CO_2$ bond order is 2.
$CO_3^{2-}$ bond order is 2.
In $CO_2$ and $CO_3^{2-}$,the C-O bond order is same.
But due to back bonding in $CO_3^{2-}$,the bond length of C-O is higher in $CO_3^{2-}$ than in $CO_2$
Hence (c) is the correct answer.
answered Mar 7, 2014 by sreemathi.v

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