# The equation of motion of a particle is given by $x=4 sin(3t)$ mts where t is in seconds . The velocity of the particle at t=0 s is

$(a)\;12\;m/s\qquad(b)\;8\;m/s\qquad(c)\;0\qquad(d)\;16\;m/s$

Answer : (a) $\;12\;m/s$
Explanation :
Equation of motion is x = 4 sint 5t
Derivating with respect to time (t)
$\large\frac{dx}{dt}$$=4\times3 \cos 3t v=\large\frac{dx}{dt}$$=12 \cos 3t \quad \; at\;t=0$
$v=12\;m/s\;.$
edited Jan 10