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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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The equation of motion of a particle is given by $x=4 sin(3t)$ mts where t is in seconds . The velocity of the particle at t=0 s is

$(a)\;12\;m/s\qquad(b)\;8\;m/s\qquad(c)\;0\qquad(d)\;16\;m/s$

Can you answer this question?
 
 

1 Answer

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Answer : (a) $\;12\;m/s$
Explanation :
Equation of motion is x = 4 sint 5t
Derivating with respect to time (t)
$\large\frac{dx}{dt}$$=4\times3 cos 3t$
$v=\large\frac{dx}{dt}$$=12 cos 3t \quad \; at\;t=0$
$v=12\;m/s\;.$
answered Mar 7, 2014 by yamini.v
edited Apr 2, 2014 by balaji.thirumalai
 

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