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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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The wave equation of 2 waves are given by $\;x_{1}=4 sin 3t\; mts\;$ and $\;x_{2}=3 cos 3t \;mts \;.$ The amplitude of the resulting wave is

$(a)\;5\;mts\qquad(b)\;6\;mts\qquad(c)\;7\;mts\qquad(d)\;1\;mts$

Can you answer this question?
 
 

1 Answer

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Answer : (a) $\;5\; mts$
Explanation :
The final wave is given by
$4 sin 3t +3 cos 3t = 5 \;(\large\frac{4}{5}\;sin 3t + \large\frac{3}{5} \;cos 3t)$
$=5 \;sin(3t+sin^{-1}(\large\frac{3}{5}))$
Therefore , wave amplitude is 5 mts .
answered Mar 7, 2014 by yamini.v
 

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