logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The change in hybridisation of the Al atom in the reaction of $AlCl_3+Cl^-\rightarrow AlCl_4^-$

$\begin{array}{1 1}(a)\;sp^2\;to\;sp^3\;hybridisation\\(b)\; sp^3\;to\;dsp^2\;hybridisation\\(c)\;dsp^2\;to\;sp^3\;hybridisation\\(d)\;\text{there is no change}\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
$AlCl_3+Cl^-\rightarrow AlCl_4^-$
$AlCl_3\Rightarrow sp^3$(Trigonal planar)
$AlCl_4^-\Rightarrow sp^3$(Tetrahydral)
Hence (d) is the correct answer.
answered Mar 7, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...