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Questions  >>  JEEMAIN and NEET  >>  Physics  >>  Class11  >>  Oscillations
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Q)

The time taken by a particle in S.H.M to reach from equilibrium position to one end is 25 s . The angular frequency w is

$(a)\;8 \pi \times 10^{-2} \;s\qquad(b)\;2 \pi \times 10^{-2} \;s\qquad(c)\;6 \pi \times 10^{-2} \;s\qquad(d)\;4 \pi \times 10^{-2} \;s$

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