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The hybridisation of N atom in $NO_2^-$ is

$\begin{array}{1 1}(a)\;sp^3&(b)\; sp^2\\(c)\;sp&(d)\;dsp^2\end{array}$

1 Answer

$sp^2-$hybridisation
Hence (b) is the correct answer.
answered Mar 7, 2014 by sreemathi.v
 

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