The hybridisation of $'Xe'$ atom in $XeF_4$ molecule is

Question

$\begin{array}{1 1}(a)\;dsp^2&(b)\; sp^3\\(c)\;sp^3d&(d)\;sp^3d^2\end{array}$

Answer 1

http://clay6.com/mpaimg/100.png

Square planar $(XeF_4)$ with $sp^3d^2$ hybridisation.

Hence (d) is the correct answer.