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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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The intensity of a sound wave is $\;10^{-6}\;w/m^2\;$. The speed of the sound wave is 343 m/s . The intensity of the medium is $\;1.2\;Kg/m^3\;$. Find the $\;(\bigtriangleup p_{max})\;$ pressure amplitude of the sound wave

$(a)\;25 \times 10^{-3}\;N/m^2\qquad(b)\;28.7 \times 10^{-3}\;N/m^2\qquad(c)\;26.9 \times 10^{-3}\;N/m^2\qquad(d)\;29.8 \times 10^{-3}\;N/m^2$

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Answer : (b) $\;28.7 \times 10^{-3}\;N/m^2$
Explanation :
Intensity (I) = $\;\large\frac{\bigtriangleup p_{max}^2}{2 \rho v}$
$\bigtriangleup p_{max}=\sqrt{2 \rho v \times I}$
$=\sqrt{2 \times 1.2 \times 343 \times 10^{-6}}$
$=28.69 \times10^{-3}\;N/m^2$
$=28.7 \times 10^{-3} N/m^2$
answered Mar 8, 2014 by yamini.v
 

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