$(a)\;53\;fB\;,37\;fB\qquad(b)\;53\;fB\;,56\;fB\qquad(c)\;53\;fB\;,60\;fB\qquad(d)\;None$

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Answer : (b) $\;53\;fB\;,56\;fB$

Explanation :

$I_{0}=10^{-12}\;w/m^{2}$

$\beta_{1}=10 log (\large\frac{2.0\times10^{-7}\;w/m^2}{10^{-12}\;w/m^2})$

$=10 log (2 \times 10^{5})$

$=53\;fB$

When both machine are operating the intensity is doubled $\;4\times 10^{-7}\;w/m^2$

$\beta_{2}=10 log(\large\frac{4 \times 10^{-7}}{10^{-12}})=10 log (4 \times 10^{5})$

$=56\;fB$

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