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The Volume occupied by molecules of one mole of gas at NTP , having radius $10^{-8}cm$ is approximately:

$(a)\;22.4L\qquad(b)\;3.72\times10^{-23}L\qquad(c)\;2.4mL\qquad(d)\;10.09mL$

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Volume of molecules in 1 mole = $4\times N\times V$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=4\times N\times \large\frac{4}{3}\pi r^3$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=4\times6.02\times10^{23}\times\large\frac{4}{3}\times\large\frac{22}{7}\times(10^{-8})$
$\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;\;=10.09mL$
Hence answer is (d)
answered Mar 9, 2014 by sharmaaparna1
 

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