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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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Find the time period of S.H.M for the following spring - mass system

$(a)\;2 \pi \sqrt{m\;(\large\frac{1}{K_{1}}+\large\frac{4}{K_{2}}+\large\frac{1}{K_{3}}+\large\frac{4}{K_{4}}+\large\frac{1}{K_{5}})}\qquad(b)\;2 \pi \sqrt{m\;(\large\frac{1}{K_{1}}+\large\frac{1}{K_{2}}+\large\frac{1}{K_{3}}+\large\frac{1}{K_{4}}+\large\frac{1}{K_{5}})}\qquad(c)\;2 \pi \sqrt{m\;(K_{1}+4K_{2}+K_{3}+4K_{4}+K_{5})}\qquad(d)\;None\;of\;these$

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Answer : (d) None of these
Explanation :
Let the springs $\;K_{1} , K_{2} , K_{3} , K_{4} ,K_{5}\;$ move by $\;x_{1} ,x_{2} ,x_{3} ,x_{4} ,x_{5}\;.$
Then the mass 'm' moves by
As the system is in equilibrium , the tension in the springs be T
By considering the F.B.D's
$2T=K_{4}x_{4} \qquad \; therefore\; , x_{4}=\large\frac{2T}{K_{4}} \;$ similarly for $\;K_{2}\;$ also
and $\;K_{5}x_{5}=T\;,K_{1}x_{1}=T\;,K_{3}x_{3}=T$
Let $\;(\large\frac{1}{K_{1}}+\large\frac{4}{K_{2}}+\large\frac{1}{K_{3}}+\large\frac{4}{K_{4}}+\large\frac{1}{K_{5}})=f$
$T=\large\frac{x}{f} \qquad (T=ma)$
$T=\large\frac{2\pi}{w}=2 \pi \sqrt{mf}$
answered Mar 10, 2014 by yamini.v
edited Mar 10, 2014 by yamini.v

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