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The ratio of Boyle's temperature and critical temperature for a gas is

$(a)\;\large\frac{8}{27}\qquad(b)\;\large\frac{27}{8}\qquad(c)\;\large\frac{1}{2}\qquad(d)\;2$

1 Answer

$T_B = \large\frac{a}{R_b}$
$T_C = \large\frac{8a}{27R_b}$
$\large\frac{T_B}{T_C} = \large\frac{a}{R_b}\times\large\frac{27R_b}{8a}$
$\;\;\;\;\;\;\;\;\;\;=\large\frac{27}{8}$
Hence answer is (b)
answered Mar 9, 2014 by sharmaaparna1
 

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