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States of Matter: Liquids and Gases
For a gas $\large\frac{R}{C_v}$$ = 0.67$ the gas may be
$(a)\;H_2\qquad(b)\;Ar.\qquad(c)\;O_3\qquad(d)\;H_2O_2$
jeemain
chemistry
states-of-matter
unit5
class11
medium
q146
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asked
Mar 9, 2014
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sharmaaparna1
retagged
Jul 10, 2014
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1 Answer
Given
$\large\frac{R}{C_v} = 0.67$
$(or) \large\frac{C_p - C_v}{C_v} = 0.67$
$(or) \large\frac{C_p}{C_v} - 1 = 0.67$ (or)
$\gamma = 1.67$
Thus gas is monoatomic , i.e Ar
Hence answer is (b)
answered
Mar 9, 2014
by
sharmaaparna1
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