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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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In the system shown the mass is at the centre on the turnatable is rotated at a constant angular speed 'w' . The equilibrium position is at (Consider the right side as positive x - axis and the springs are initially unstretched )

$(a)\;\large\frac{K_{1}+K_{2}}{mw^2}\qquad(b)\;\large\frac{K_{1}K_{2}}{(K_{1}+K_{2})w^2m}\qquad(c)\;\large\frac{(K_{1}+K_{2})}{w^2}\qquad(d)\;None\;of\;these$

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1 Answer

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Answer : (d) None of these
Explanation :
As the mass is at the centre of the table , the centrifugal force on it is zero as radius (r=0)
answered Mar 10, 2014 by yamini.v
 

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