Browse Questions

Find the bond angle of $H_2S$.If the S-H bond moment is 0.72D and $\mu=0.95D$

$\begin{array}{1 1}(a)\;\theta=13^{\large\circ}&(b)\;\theta=104^{\large\circ}\\(c)\;\theta=72^{\large\circ}&(d)\;\theta=97^{\large\circ}\end{array}$

Net dipole moment $\mu=2(\text{bond moment})\times \cos\large\frac{\theta}{2}$
$0.95D=2(0.72D)\times \cos\large\frac{\theta}{2}$
$\cos\large\frac{\theta}{2}$$=0.6597$
Bond angle $\theta=97^{\large\circ}$
Hence (d) is the correct answer.