logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Polarisation of electrons in acrolein may be written as :

$\begin{array}{1 1}(a)\;CH_2^{\delta -}=CH-CH^{\delta +}=O\\(b)\; CH_2^{\delta -}=CH-CH=O^{\delta +}\\(c)\; CH_2^{\delta -}=CH^{\delta +}-CH=O\\(d)\; CH_2^{\delta +}=CH-CH=O^{\delta -}\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
$CH_2^{\delta +}=CH-CH=O^{\delta -}$
Because here,'O' is more electronegative ,hence it should take negative charge.
Hence (d) is the correct answer.
answered Mar 10, 2014 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...