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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Oscillations
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The angular frequency 'w' of the system is

$(a)\;1\;rad/s\qquad(b)\;2\;rad/s\qquad(c)\;1.5\;rad/s\qquad(d)\;0.5\;rad/s$
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Answer : (a) $\;1\;rad/s$
Explanation :
First $\;3 \times 6\;$ and $\;6 \times 12\;$ are in series
Therefore , $\;\large\frac{3 \times 6}{9}\;$ and $\;\large\frac{6 \times12}{18}\;$ are in parallel
Therefore, the equivalent spring constant of the system is $\;2+4=6 N/m$
The angular frequency $\;w=\sqrt{\large\frac{K}{m}}$
$=\sqrt{\large\frac{6}{6}}$
$=1$
$w=1\; rad/s\;.$
answered Mar 11, 2014 by yamini.v
edited Mar 23, 2014 by balaji.thirumalai
 

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