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The correct order of ionization energy is :

$ (a)\;Si > P > S \\(b)\; Si > P < S \\ (c)\;Si < P > S \\ (d)\;Si < P < S $

1 Answer

Solution :
Phosphorus has maximum ionization energy because of its half- filled electronic configuration .
The correct order is :$ Si < P > S$
Hence c is the correct answer.
answered Mar 11, 2014 by meena.p
edited Oct 4 by meena.p
 

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