$C_v = C_p - R = 1.5$

The amount of gas is given by $n = \large\frac{PV}{RT} $$ = \large\frac{10^5 \times 0.083}{8.3 \times 600} $$= 1.67$

Therefore, $\Delta u = n C_v \Delta T = \Delta Q$ (Because, work done = 0)

$\Rightarrow 200 = \large\frac{5}{3} $$\times 1.5R \times \Delta T \rightarrow \Delta T = 9.64K$

$\Rightarrow$ New Temperature $= 609.64 ^{\circ} K$

$\Rightarrow $ New Pressure $= \large\frac{609.64}{600}$$\times 10^5 = 1.02 \times 10^5$ $N/m^2$